coursera python assignment 7.1

Python Data Structures

Week 1 - assignment 6.5.

Write code using find() and string slicing to extract the number at the end of the line below. Convert the extracted value to a floating point number and print it out.

text = "X-DSPAM-Confidence: 0.8475";

text = "X-DSPAM-Confidence: 0.8475"

Colpos = text.find(':') # Colon Position

text_a_Colpos = text[Colpos+1 : ] # Text after colon position

number = text_a_Colpos.strip()

print(float(number))

ans = float(text_a_Colpos)

# Using Split and join functions

num_str = text_a_Colpos.split() # string format of number in list

d = ""

num = d.join(num_str) # converts list into string

num_f = float(num)

print(num_f)

=============================================================================================

Week 3 - Assignment 7.1

Write a program that prompts for a file name, then opens that file and reads through the file, and print the contents of the file in upper case. Use the file words.txt to produce the output below.

when you are testing below enter words.txt as the file name.

file = input('Enter the file name: ')

fhandle = open(file)

for line in fhandle:

line_strip = line.strip()

line = line_strip.upper()

print(line)

Assignment 7.2

Write a program that prompts for a file name, then opens that file and reads through the file, looking for lines of the form:

X-DSPAM-Confidence: 0.8475

Count these lines and extract the floating point values from each of the lines and compute the average of those values and produce an output as shown below. Do not use the sum() function or a variable named sum in your solution.

when you are testing below enter mbox-short.txt as the file name.

fname = input('Enter the file name: ')

fhandle = open(fname)

for line in fhandle :

if 'X-DSPAM-Confidence:' in line :

Colpos = line.find(':')

num_string = line[Colpos + 1 : ]

num = float(num_string)

count = count + 1

Total = Total + num

avg = Total / count

print('Average spam confidence:',avg)

===============================================================================================

Week 4 - Assignment 8.4

Open the file romeo.txt and read it line by line. For each line, split the line into a list of words using the split() method. The program should build a list of words. For each word on each line check to see if the word is already in the list and if not append it to the list. When the program completes, sort and print the resulting words in alphabetical order.

fhandle = open('romeo.txt')

lst = list()

words = line.split()

print(words)

for word in words:

if lst is None:

lst.append(word)

elif word in lst:

Assignment 8.5

Open the file mbox-short.txt and read it line by line. When you find a line that starts with 'From ' like the following line:

From [email protected] Sat Jan 5 09:14:16 2008

You will parse the From line using split() and print out the second word in the line (i.e. the entire address of the person who sent the message). Then print out a count at the end.

Hint: make sure not to include the lines that start with 'From:'.

if line.startswith('From') :

if line[4] is ':' :

req_line = line.split()

print(req_line[1])

print('There were',count, 'lines in the file with From as the first word')

==============================================================================================

Week 5 - Assignment 9.4

Write a program to read through the mbox-short.txt and figure out who has sent the greatest number of mail messages. The program looks for 'From ' lines and takes the second word of those lines as the person who sent the mail. The program creates a Python dictionary that maps the sender's mail address to a count of the number of times they appear in the file. After the dictionary is produced, the program reads through the dictionary using a maximum loop to find the most prolific committer.

reg_mailer = dict() # regular mailer

mail = words[1]

# reg_mailer[mail] = reg_mailer.get(mail,0) + 1

if reg_mailer is None or mail not in reg_mailer :

reg_mailer[mail] = 1

reg_mailer[mail] = reg_mailer[mail] + 1

a = max(reg_mailer.values())

for key, value in reg_mailer.items() :

if value == a :

print(key,a)

Week 6 - Assignment 10.2

Write a program to read through the mbox-short.txt and figure out the distribution by hour of the day for each of the messages.

You can pull the hour out from the 'From ' line by finding the time and then splitting the string a second time using a colon.

Once you have accumulated the counts for each hour, print out the counts, sorted by hour as shown below.

time_mail = dict()

time = words[5]

time_tup = time.split(':')

time_tuple = time_tup[0]

time_mail[time_tuple] = time_mail.get(time_tuple,0) + 1

# if reg_mailer is None or mail not in reg_mailer :

# reg_mailer[mail] = 1

# reg_mailer[mail] = reg_mailer[mail] + 1

ans = sorted(time_mail.items())

for k,v in ans:

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Current repository contains all assignments, notes, quizzes and course materials from the "Python for Everybody Specialization" provided by Coursera and University of Michigan.

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Coursera Python for Everybody specialization is offered by University of Michigan.

Specialization includes following courses:

• Getting started with python
• Python Data Structures
• Using python to Access Web Data
• Using Databases with Python
• Capstone: Retrieving Processing and Visualizing Data with Python

Each course described above contains assignments answers, course material and might contain some notes. Some course slides seemed to awesome and entartaining for me, so I could not resist adding all of them here 😃.

Additional materials

All additional course materials also can be found here . Also here is the link to the HTML version of Charles R. Severance book.

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Without him existing on a planet I probably would never quit civil engineering and got interest in programming at all. Professor Charles Severance, University of Michigan.

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