python dictionary typeerror 'set' object does not support item assignment

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TypeError: Type object does not support item assignment: How to fix it?

TypeError: Type object does not support item assignment

Have you ever tried to assign a value to a property of a type object and received a TypeError? If so, you’re not alone. This error is a common one, and it can be frustrating to figure out what went wrong.

In this article, we’ll take a look at what a type object is, why you can’t assign values to its properties, and how to avoid this error. We’ll also provide some examples of how to work with type objects correctly.

So, if you’re ready to learn more about TypeErrors and type objects, read on!

What is a type object?

A type object is a special kind of object that represents a data type. For example, the `int` type object represents the integer data type, and the `str` type object represents the string data type.

Type objects are created when you use the `type()` function. For example, the following code creates a type object for the integer data type:

python int_type = type(1)

Type objects have a number of properties that you can use to get information about them. For example, the `__name__` property returns the name of the type, and the `__bases__` property returns a list of the type’s base classes.

Why can’t you assign values to type objects?

Type objects are immutable, which means that their values cannot be changed. This is because type objects are used to represent the abstract concept of a data type, and their values are not meant to be changed.

If you try to assign a value to a property of a type object, you’ll receive a TypeError. For example, the following code will raise a TypeError:

python int_type.name = “New name”

How to avoid TypeErrors

To avoid TypeErrors, you should never try to assign values to properties of type objects. If you need to change the value of a property, you should create a new object with the desired value.

For example, the following code correctly changes the value of the `name` property of an integer object:

python new_int = int(1) new_int.name = “New name”

TypeErrors can be frustrating, but they can usually be avoided by understanding what type objects are and how they work. By following the tips in this article, you can avoid these errors and write more robust code.

| Header 1 | Header 2 | Header 3 | |—|—|—| | TypeError: type object does not support item assignment | Definition | Cause | | An error that occurs when you try to assign a value to an element of a type object that does not support item assignment. | The type object is immutable, which means that its values cannot be changed. | Trying to assign a value to an element of a type object will result in a TypeError. |

A TypeError is a type of error that occurs when an operation or function is applied to an object of an inappropriate type. For example, trying to assign a value to an attribute of a type object will result in a TypeError.

TypeErrors can be difficult to debug, because they can occur in a variety of situations. However, by understanding what causes a TypeError, you can be better equipped to avoid them.

What causes a TypeError?

There are a few different things that can cause a TypeError:

• Using an incompatible data type: One of the most common causes of a TypeError is using an incompatible data type. For example, trying to add a string to a number will result in a TypeError.
• Using an invalid operator: Another common cause of a TypeError is using an invalid operator. For example, trying to divide a number by zero will result in a TypeError.
• Calling a method on an object that doesn’t support it: Finally, trying to call a method on an object that doesn’t support it can also result in a TypeError. For example, trying to call the `.sort()` method on a string will result in a TypeError.

There are a few things you can do to avoid TypeErrors:

• Be careful about the data types you use: Make sure that you are using the correct data types for your operations. For example, if you are adding two numbers, make sure that both numbers are numbers.
• Use the correct operators: Make sure that you are using the correct operators for your operations. For example, if you are dividing two numbers, use the `/` operator.
• Read the documentation: If you are not sure whether a method is supported by an object, read the documentation to find out.

By following these tips, you can help to avoid TypeErrors in your code.

TypeErrors can be a frustrating experience, but they can also be a learning opportunity. By understanding what causes a TypeError, you can be better equipped to avoid them. And by following the tips in this article, you can help to reduce the number of TypeErrors in your code.

Additional resources

• [Python TypeError documentation](https://docs.python.org/3/library/exceptions.htmlTypeError)
• [Stack Overflow: TypeError questions](https://stackoverflow.com/questions/tagged/typeerror)
• [Real Python: How to avoid TypeErrors in Python](https://realpython.com/python-typeerror/)

3. How to fix a TypeError?

To fix a TypeError, you need to identify the cause of the error and then take steps to correct it. Some common fixes include:

Using the correct data type

Using the correct operator

Calling the correct method on the object

Let’s take a look at some examples of how to fix each of these types of errors.

One of the most common causes of TypeErrors is using the wrong data type. For example, if you try to add a string to an integer, you will get a TypeError because strings and integers are different data types. To fix this error, you need to convert the string to an integer or the integer to a string.

x = ‘123’ y = 456

This will raise a TypeError because you cannot add a string to an integer z = x + y

To fix this error, you can convert the string to an integer z = int(x) + y

Another common cause of TypeErrors is using the wrong operator. For example, if you try to divide an integer by a string, you will get a TypeError because you cannot divide an integer by a string. To fix this error, you need to use the correct operator.

x = 123 y = ‘456’

This will raise a TypeError because you cannot divide an integer by a string z = x / y

To fix this error, you can use the `str()` function to convert the string to an integer z = x / int(y)

Finally, another common cause of TypeErrors is calling the wrong method on an object. For example, if you try to call the `len()` method on a string, you will get a TypeError because the `len()` method is not defined for strings. To fix this error, you need to call the correct method on the object.

x = ‘hello’

This will raise a TypeError because the `len()` method is not defined for strings y = len(x)

To fix this error, you can use the `str()` function to convert the string to an integer y = len(str(x))

By following these tips, you can help to avoid TypeErrors in your Python code.

4. Examples of TypeErrors

Here are some examples of TypeErrors:

x = ‘hello’ x[0] = ‘a’

This will result in a TypeError because strings are immutable and cannot be changed.

print(int(‘123’))

This will also result in a TypeError because the string ‘123’ cannot be converted to an integer.

class MyClass: def __init__(self, name): self.name = name

my_class = MyClass(‘John’) my_class.name = ‘Jane’

This will also result in a TypeError because the method `name` is not defined on the `MyClass` object.

TypeErrors are a common problem in Python, but they can be easily avoided by following the tips in this article. By using the correct data types, operators, and methods, you can help to ensure that your Python code is free of errors.

Q: What does the error “TypeError: type object does not support item assignment” mean?

A: This error occurs when you try to assign a value to a property of a type object. For example, the following code will raise an error:

>>> type = type(‘MyType’, (object,), {}) >>> type.name = ‘MyType’ Traceback (most recent call last): File “ “, line 1, in TypeError: type object does not support item assignment

The reason for this error is that type objects are immutable, which means that their properties cannot be changed after they are created. If you need to change the value of a property of a type object, you can create a new type object with the desired value.

Q: How can I fix the error “TypeError: type object does not support item assignment”?

A: There are two ways to fix this error. The first way is to create a new type object with the desired value. For example, the following code will fix the error in the example above:

>>> type = type(‘MyType’, (object,), {‘name’: ‘MyType’}) >>> type.name ‘MyType’

The second way to fix this error is to use a dictionary to store the properties of the type object. For example, the following code will also fix the error in the example above:

>>> type = type(‘MyType’, (object,), {}) >>> type.__dict__[‘name’] = ‘MyType’ >>> type.name ‘MyType’

Q: What are some common causes of the error “TypeError: type object does not support item assignment”?

A: There are a few common causes of this error. The first is trying to assign a value to a property of a type object that does not exist. For example, the following code will raise an error:

>>> type = type(‘MyType’, (object,), {}) >>> type.foo = ‘bar’ Traceback (most recent call last): File “ “, line 1, in AttributeError: type object has no attribute ‘foo’

The second is trying to assign a value to a property of a type object that is read-only. For example, the following code will also raise an error:

>>> type = type(‘MyType’, (object,), {}) >>> type.name = ‘MyType’ Traceback (most recent call last): File “ “, line 1, in TypeError: can’t set attribute ‘name’ of type object

The third is trying to assign a value to a property of a type object that is not a valid type. For example, the following code will also raise an error:

>>> type = type(‘MyType’, (object,), {}) >>> type.name = 123 Traceback (most recent call last): File “ “, line 1, in TypeError: can’t assign int to str object

Q: How can I avoid the error “TypeError: type object does not support item assignment”?

A: There are a few things you can do to avoid this error. First, make sure that you are trying to assign a value to a property of a type object that exists. Second, make sure that you are not trying to assign a value to a property of a type object that is read-only. Third, make sure that you are not trying to assign a value to a property of a type object that is not a valid type.

Here are some specific examples of how to avoid this error:

• Instead of trying to assign a value to the `name` property of a type object, you can create a new type object with the desired value. For example:

>>> type = type(‘MyType’, (object,), {‘name’: ‘MyType’})

• Instead of trying to assign a value to the `name` property of a type object, you can use a dictionary to store the properties of the type object. For example:

>>> type = type(‘MyType’, (object,), {}) >>> type.__dict__[‘name’] = ‘MyType’

• Instead of trying to assign a value to the `name` property of a type object, you can use a getter and setter method to access the property. For example:

In this blog post, we discussed the TypeError: type object does not support item assignment error. We first explained what the error is and then provided several ways to fix it. We also discussed some common causes of the error and how to avoid them.

We hope that this blog post has been helpful and that you now have a better understanding of the TypeError: type object does not support item assignment error. If you have any other questions or comments, please feel free to leave them below.

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'set' object does not support item assignment 11/14

Hey show im on 11/14 of list and dictionaries but it keeps giving me an error saying: 'set' object does not support item assignment . So im not sure what the problem is or is it a glitch so here’s my code help would be appreciated

Thxs again and yes my menu is a bit crazy

Answer 53e1389a282ae363cf00082c

You’re not assigning values to the keys when you create menu . Look at what they did for residents:

I think they wanted you to add more key-value pairs (no need to print them) using this method. The section is over how dictionaries are mutable (able to change after creation) and so your changing the dictionary by adding key-value pairs like this:

Answer 53e1552052f863cf4a000cb0

Yes, use key-value pairs in the curly braces, as @Kosz says. The way you have it here, you have created a set instead of a dictionary.

Answer 53e225da7c82ca052900278e

Thxs for your answers guys it worked i tried first and it didn’t and tried again and it did thxs alot

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• TypeError: 'str' object does not support item assignment

Last updated: Apr 8, 2024 Reading time · 8 min

# Table of Contents

• TypeError: 'int' object does not support item assignment
• 'numpy.float64' object does not support item assignment

# TypeError: 'str' object does not support item assignment

The Python "TypeError: 'str' object does not support item assignment" occurs when we try to modify a character in a string.

Strings are immutable in Python, so we have to convert the string to a list, replace the list item and join the list elements into a string.

Here is an example of how the error occurs.

We tried to change a specific character of a string which caused the error.

Strings are immutable, so updating the string in place is not an option.

Instead, we have to create a new, updated string.

# Using str.replace() to get a new, updated string

One way to solve the error is to use the str.replace() method to get a new, updated string.

The str.replace() method returns a copy of the string with all occurrences of a substring replaced by the provided replacement.

The method takes the following parameters:

By default, the str.replace() method replaces all occurrences of the substring in the string.

If you only need to replace the first occurrence, set the count argument to 1 .

Setting the count argument to 1 means that only the first occurrence of the substring is replaced.

# Replacing a character with a conversion to list

One way to replace a character at a specific index in a string is to:

• Convert the string to a list.
• Update the list item at the specified index.
• Join the list items into a string.

We passed the string to the list() class to get a list containing the string's characters.

The last step is to join the list items into a string with an empty string separator.

The str.join() method takes an iterable as an argument and returns a string which is the concatenation of the strings in the iterable.

Python indexes are zero-based, so the first character in a string has an index of 0 , and the last character has an index of -1 or len(a_string) - 1 .

If you have to do this often, define a reusable function.

The update_str function takes a string, index and new characters as parameters and returns a new string with the character at the specified index updated.

An alternative approach is to use string slicing .

# Reassigning a string variable

If you need to reassign a string variable by adding characters to it, use the += operator.

The += operator is a shorthand for my_str = my_str + 'new' .

The code sample achieves the same result as using the longer form syntax.

# Using string slicing to get a new, updated string

Here is an example that replaces an underscore at a specific index with a space.

The first piece of the string we need is up to, but not including the character we want to replace.

The syntax for string slicing is a_string[start:stop:step] .

The start index is inclusive, whereas the stop index is exclusive (up to, but not including).

The slice my_str[0:idx] starts at index 0 and goes up to, but not including idx .

The next step is to use the addition + operator to add the replacement string (in our case - a space).

The last step is to concatenate the rest of the string.

Notice that we start the slice at index + 1 because we want to omit the character we are replacing.

We don't specify an end index after the colon, therefore the slice goes to the end of the string.

We simply construct a new string excluding the character at the specified index and providing a replacement string.

If you have to do this often define a reusable function.

The function takes a string, index and a replacement character as parameters and returns a new string with the character at the specified index replaced.

If you need to update multiple characters in the function, use the length of the replacement string when slicing.

The function takes one or more characters and uses the length of the replacement string to determine the start index for the second slice.

If the user passes a replacement string that contains 2 characters, then we omit 2 characters from the original string.

# TypeError: 'int' object does not support item assignment

The Python "TypeError: 'int' object does not support item assignment" occurs when we try to assign a value to an integer using square brackets.

To solve the error, correct the assignment or the accessor, as we can't mutate an integer value.

We tried to change the digit at index 0 of an integer which caused the error.

# Declaring a separate variable with a different name

If you meant to declare another integer, declare a separate variable with a different name.

# Changing an integer value in a list

Primitives like integers, floats and strings are immutable in Python.

If you meant to change an integer value in a list, use square brackets.

Python indexes are zero-based, so the first item in a list has an index of 0 , and the last item has an index of -1 or len(a_list) - 1 .

We used square brackets to change the value of the list element at index 0 .

# Updating a value in a two-dimensional list

If you have two-dimensional lists, you have to access the list item at the correct index when updating it.

We accessed the first nested list (index 0 ) and then updated the value of the first item in the nested list.

# Reassigning a list to an integer by mistake

Make sure you haven't declared a variable with the same name multiple times and you aren't reassigning a list to an integer somewhere by mistake.

We initially declared the variable and set it to a list, however, it later got set to an integer.

Trying to assign a value to an integer causes the error.

To solve the error, track down where the variable got assigned an integer and correct the assignment.

# Getting a new list by running a computation

If you need to get a new list by running a computation on each integer value of the original list, use a list comprehension .

The Python "TypeError: 'int' object does not support item assignment" is caused when we try to mutate the value of an int.

# Checking what type a variable stores

If you aren't sure what type a variable stores, use the built-in type() class.

The type class returns the type of an object.

The isinstance() function returns True if the passed-in object is an instance or a subclass of the passed-in class.

# 'numpy.float64' object does not support item assignment

The Python "TypeError: 'numpy.float64' object does not support item assignment" occurs when we try to assign a value to a NumPy float using square brackets.

To solve the error, correct the assignment or the accessor, as we can't mutate a floating-point number.

We tried to change the digit at index 0 of a NumPy float.

# Declaring multiple floating-point numbers

If you mean to declare another floating-point number, simply declare a separate variable with a different name.

# Floating-point numbers are immutable

Primitives such as floats, integers and strings are immutable in Python.

If you need to update a value in an array of floating-point numbers, use square brackets.

We changed the value of the array element at index 0 .

# Reassigning a variable to a NumPy float by mistake

Make sure you haven't declared a variable with the same name multiple times and you aren't reassigning a list to a float somewhere by mistake.

We initially set the variable to a NumPy array but later reassigned it to a floating-point number.

Trying to update a digit in a float causes the error.

# When working with two-dimensional arrays

If you have a two-dimensional array, access the array element at the correct index when updating it.

We accessed the first nested array (index 0 ) and then updated the value of the first item in the nested array.

The Python "TypeError: 'float' object does not support item assignment" is caused when we try to mutate the value of a float.

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Web Developer

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TypeError: 'src' object does not support item assignment

The assignment str[i] = str[j] is working inconsistently. Please refer to the screenshots and let me know if I am missing something.

We are receiving TypeError: ‘src’ object does not support item assignment

Regards, Praveen. Thank you!

Please don’t use screenshots. Show the code and the traceback as text.

Strings are immutable. You can’t modify a string by trying to change a character within.

You can create a new string with the bits before, the bits after, and whatever you want in between.

Yeah, you cannot assign a string to a variable, and then modify the string, but you can use the string to create a new one and assign that result to the same variable. Borrowing some code from @BowlOfRed above, you can do this:

[Solved] TypeError: ‘str’ Object Does Not Support Item Assignment

In this article, we will be discussing the TypeError:’str’ Object Does Not Support Item Assignment exception . We will also be going through solutions to this problem with example programs.

Why is This Error Raised?

When you attempt to change a character within a string using the assignment operator, you will receive the Python error TypeError: ‘str’ object does not support item assignment.

As we know, strings are immutable. If you attempt to change the content of a string, you will receive the error TypeError: ‘str’ object does not support item assignment .

There are four other similar variations based on immutable data types :

• TypeError: 'tuple' object does not support item assignment
• TypeError: 'int' object does not support item assignment
• TypeError: 'float' object does not support item assignment
• TypeError: 'bool' object does not support item assignment

Replacing String Characters using Assignment Operators

Replicate these errors yourself online to get a better idea here .

In this code, we will attempt to replace characters in a string.

Strings are an immutable data type. However, we can change the memory to a different set of characters like so:

TypeError: ‘str’ Object Does Not Support Item Assignment in JSON

Let’s review the following code, which retrieves data from a JSON file.

In line 5, we are assigning data['sample'] to a string instead of an actual dictionary. This causes the interpreter to believe we are reassigning the value for an immutable string type.

TypeError: ‘str’ Object Does Not Support Item Assignment in PySpark

The following program reads files from a folder in a loop and creates data frames.

This occurs when a PySpark function is overwritten with a string. You can try directly importing the functions like so:

TypeError: ‘str’ Object Does Not Support Item Assignment in PyMongo

The following program writes decoded messages in a MongoDB collection. The decoded message is in a Python Dictionary.

At the 10th visible line, the variable x is converted as a string.

It’s better to use:

Please note that msg are a dictionary and NOT an object of context.

TypeError: ‘str’ Object Does Not Support Item Assignment in Random Shuffle

The below implementation takes an input main and the value is shuffled. The shuffled value is placed into Second .

random.shuffle is being called on a string, which is not supported. Convert the string type into a list and back to a string as an output in Second

TypeError: ‘str’ Object Does Not Support Item Assignment in Pandas Data Frame

The following program attempts to add a new column into the data frame

The iteration statement for dataset in df: loops through all the column names of “sample.csv”. To add an extra column, remove the iteration and simply pass dataset['Column'] = 1 .

These are the causes for TypeErrors : – Incompatible operations between 2 operands: – Passing a non-callable identifier – Incorrect list index type – Iterating a non-iterable identifier.

The data types that support item assignment are: – Lists – Dictionaries – and Sets These data types are mutable and support item assignment

As we know, TypeErrors occur due to unsupported operations between operands. To avoid facing such errors, we must: – Learn Proper Python syntax for all Data Types. – Establish the mutable and immutable Data Types. – Figure how list indexing works and other data types that support indexing. – Explore how function calls work in Python and various ways to call a function. – Establish the difference between an iterable and non-iterable identifier. – Learn the properties of Python Data Types.

We have looked at various error cases in TypeError:’str’ Object Does Not Support Item Assignment. Solutions for these cases have been provided. We have also mentioned similar variations of this exception.

Trending Python Articles

Fix Python TypeError: 'str' object does not support item assignment

This error occurs because a string in Python is immutable, meaning you can’t change its value after it has been defined.

Another way you can modify a string is to use the string slicing and concatenation method.

Take your skills to the next level ⚡️

How to Solve Python TypeError: ‘str’ object does not support item assignment

by Suf | Programming , Python , Tips

Strings are immutable objects, which means you cannot change them once created. If you try to change a string in place using the indexing operator [], you will raise the TypeError: ‘str’ object does not support item assignment.

To solve this error, you can use += to add characters to a string.

a += b is the same as a = a + b

Generally, you should check if there are any string methods that can create a modified copy of the string for your needs.

This tutorial will go through how to solve this error and solve it with the help of code examples.

Table of contents

Python typeerror: ‘str’ object does not support item assignment, solution #1: create new string using += operator, solution #2: create new string using str.join() and list comprehension.

Let’s break up the error message to understand what the error means. TypeError occurs whenever you attempt to use an illegal operation for a specific data type.

The part 'str' object tells us that the error concerns an illegal operation for strings.

The part does not support item assignment tells us that item assignment is the illegal operation we are attempting.

Strings are immutable objects which means we cannot change them once created. We have to create a new string object and add the elements we want to that new object. Item assignment changes an object in place, which is only suitable for mutable objects like lists. Item assignment is suitable for lists because they are mutable.

Let’s look at an example of assigning items to a list. We will iterate over a list and check if each item is even. If the number is even, we will assign the square of that number in place at that index position.

Let’s run the code to see the result:

We can successfully do item assignment on a list.

Let’s see what happens when we try to change a string using item assignment:

We cannot change the character at position -1 (last character) because strings are immutable. We need to create a modified copy of a string, for example using replace() :

In the above code, we create a copy of the string using = and call the replace function to replace the lower case h with an upper case H .

Let’s look at another example.

In this example, we will write a program that takes a string input from the user, checks if there are vowels in the string, and removes them if present. First, let’s define the vowel remover function.

We check if each character in a provided string is a member of the vowels list in the above code. If the character is a vowel, we attempt to replace that character with an empty string. Next, we will use the input() method to get the input string from the user.

Altogether, the program looks like this:

The error occurs because of the line: string[ch] = "" . We cannot change a string in place because strings are immutable.

We can solve this error by creating a modified copy of the string using the += operator. We have to change the logic of our if statement to the condition not in vowels . Let’s look at the revised code:

Note that in the vowel_remover function, we define a separate variable called new_string , which is initially empty. If the for loop finds a character that is not a vowel, we add that character to the end of the new_string string using += . We check if the character is not a vowel with the if statement: if string[ch] not in vowels .

We successfully removed all vowels from the string.

We can solve this error by creating a modified copy of the string using list comprehension. List comprehension provides a shorter syntax for creating a new list based on the values of an existing list.

Let’s look at the revised code:

In the above code, the list comprehension creates a new list of characters from the string if the characters are not in the list of vowels. We then use the join() method to convert the list to a string. Let’s run the code to get the result:

We successfully removed all vowels from the input string.

Congratulations on reading to the end of this tutorial. The TypeError: ‘str’ object does not support item assignment occurs when you try to change a string in-place using the indexing operator [] . You cannot modify a string once you create it. To solve this error, you need to create a new string based on the contents of the existing string. The common ways to change a string are:

• List comprehension
• The String replace() method
• += Operator

For further reading on TypeErrors, go to the articles:

• How to Solve Python TypeError: object of type ‘NoneType’ has no len()
• How to Solve Python TypeError: ‘>’ not supported between instances of ‘str’ and ‘int’
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[SOLVED] TypeError: ‘str’ object does not support item assignment

“ TypeError: ‘str’ object does not support item assignment ” error message occurs when you try to change individual characters in a string. In python, strings are immutable, which means their values can’t be changed after they are created.

How to fix TypeError: str object does not support item assignment

In conclusion, the “ TypeError: ‘str’ object does not support item assignment ” error in Python occurs when you try to modify an individual character in a string, which is not allowed in Python since strings are immutable. To resolve this issue, you can either convert the string to a list of characters, make the desired changes, and then join the list back into a string, or you can create a new string with the desired changes by using string slicing and concatenation.

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TypeError: 'int' object does not support item assignment

Im getting this error and don't know how to fix it...

4 Answers 4

You are presumably trying to build a list of length lenp here. You'd need to create a list by multiplication here:

but you'd be better off building the list by appending to it:

where you don't use p[i] but i directly ; Python for loops are for each loops really.

Your range() produces values in the series [0, 10, 20, ... 1200) and the for loop assigns each of those values to i per iteration. If you use i to index into p again you'd run into problems; p[0] would still be 0 , but p[10] would then be 100 , p[20] is 200 , etc. until p[120] throws an IndexError because there are only 119 different values in that range.

You can collapse the for loop appending to Temp into a list comprehension to build the list in one go:

There are a couple of issues in your code.

The most immediate one is that your Temp value is not a sequence that you can assign things to, just an integer (the parentheses don't do anything). While you could make it into a tuple by adding a comma, that still won't let you assign values into Temp after it has been created (tuples are immutable). Instead, you probably want a list.

However, there's another issue with your loop. A for loop like for value in sequence assigns values from the sequence to the variable value . It doesn't assign indexes! If you need indexes, you can either use enumerate or use a different looping construct, such as a list comprehension.

Here's a minimally changed version of your code that first creates a list of lenp zeros, then replaces their values with the computed ones:

Here's a more pythonic version that uses a list comprehension instead of an ordinary loop:

Your Temp is not a tuple, it's just an integer in parenthesis. You can fix this with a simple , . Consider the following:

However , tuples are immutable, and you cannot perform such an assignment:

You can fix this issue by using a list instead.

• But the OP is trying to assign to indices; a tuple won't allow that. –  Martijn Pieters Commented Jan 27, 2014 at 20:15
• By adding the comma the OP can index into x , but still won't be able to modify it, for two reasons: (1) tuples are immutable. (2) i is looping over values which aren't really tuple or array indices. –  DSM Commented Jan 27, 2014 at 20:16
• @MartijnPieters Yes, that's a good point. I'll edit the answer. –  arshajii Commented Jan 27, 2014 at 20:16

The mistake is that when we assign a (number) to x, this is what is actually happening,

So if you want to create an empty list , you can do it this way

Its gonna create something like this one,

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