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Subscripted assignment dimension mismatch.
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- subscripted assignment dimension mismatch
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Subscripted assignment dimension mismatch error
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- %D0=25x25 image(double)
- %Y=25x5000 signal(double)
- [m,n0] = size(D0);
- [~,N] = size(Y);
- itcmat = zeros(iters/iter_check, n0-nmin+1);
- D0run = D0;
- vn = [n0]; % vector of actual sizes
- for it = 1 : iter_check : iters
- % run the algorithm for a few iterations
- [D, X, ~] = DL(Y, D0run, s, iter_check, str2func(update), params, 'replatom', replatom);
- % order dictionary based on representation power
- [~, atom_list] = sort(sum(X.*X,2), 'descend');
- % compute ITC for all dictionary sizes (with ordered atoms)
- n1 = max(nmin, vn(ii) - ncand);
- for n2 = n1 : vn(ii)
- Dn = D(:, atom_list(1:n2));
- Xn = omp(Y, Dn, s);
- rmse = norm(Y-Dn*Xn, 'fro')/sqrt(m*N);
- if itc_index > 10
- itc2 = com_itc_BS_2( Y, Dn, Xn, rmse );
- itcmat(ii,n2-n1+1) = itc2(itc_index-10);
- [~, itc2] = com_itc_BS( Y, Dn, Xn, rmse );
- itcmat(ii,n2-n1+1) = itc2(itc_index);
- % trim or enlarge dictionary
- [~,n2] = min(itcmat(ii,1:vn(ii)-n1+1)); % compute min value of ITC
- n2 = n2 + n1 - 1;
- nopt(ii) = n2; % % error Subscripted assignment dimension mismatch.
- itcmat(ii,vn(ii)-n1+2:n0-n1+1) = itcmat(ii,vn(ii)-n1+1); % fill with last value of ITC
- if n2 < vn(ii) - nminus % dictionary is too big
- n2 = max(nmin, vn(ii) - nminus);
- D0run = D(:, atom_list(1:n2)); % continue with new dictionary
- elseif n2 < vn(ii)-1
- n2 = max(nmin, vn(ii) - 1);
- elseif n2 == vn(ii) % dictionay may be too small, increase size
- %n = vn(ii);
- n2 = vn(ii) + nplus;
- Dplus = randn(m,nplus);
- Dplus = normc(Dplus);
- D0run = [D Dplus]; % continue with new dictionary
- vn(ii+1) = n2;
- % final operations
- X = omp(Y, D0run, s); % compute RMSE just to see it
- rmse = norm(Y-D0run*X, 'fro')/sqrt(m*N);
- rmsev(ii) = rmse;
- % final refinement: a few DL iterations with the final size
- if nopt(ii-1) < vn(ii-1)
- D0run = D(:, atom_list(1:nopt(ii-1))); % cut dictionary to optimal number of atoms
- [D, ~, ~] = DL(Y, D0run, s, iter_check, str2func(update), params, 'replatom', replatom);
- X = omp(Y, D, s);
- rmse = norm(Y-D*X, 'fro')/sqrt(m*N);
- rmse = norm(Y-D0run*X, 'fro' )/sqrt(m*N);
- [D, ~, ~] = DL(Y, D0run, s, iter_check, str2func(update), params, 'replatom' , replatom);
- rmse = norm(Y-D*X, 'fro' )/sqrt(m*N);
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- assigning arrays of different size
- Image Processing Toolbox
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错误提示：Subscripted assignment dimension mismatch.。
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https://www.mathworks.com/matlabcentral/answers/1860198-subscripted-assignment-dimension-mismatch
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In this case, 'A' has size 2x3, that is, 2 rows and 3 columns. The vector 'B' has size 1x4, 1 row and 4 columns. The assignment statement attempts to replace the second row of 'A' with the row vector 'B', but this is not possible because 'B' has 4 columns, and 'A' only has 3 columns.
For the case where you are assigning values for every pairwise combination, here are a couple of the ways you can do it: Break up the assignment into 3 steps, one for each plane in the third dimension: new_img(rows,cols,1) = curMean(1); %# Assignment for the first plane. new_img(rows,cols,2) = curMean(2); %# Assignment for the second plane.
Learn more about subscripted assignment dimension mismatch., subscripted assignment dimension mismatch, subscripted assignment dimension mismatch for loop Here is the code that I'm getting the error: for z=1:length(X) V(z)=[X(z):Y]; end where X is a 1x81 matrix and Y is an integer
Why do I get the "Subscripted assignment... Learn more about subscripted, assignment, dimension, mismatch MATLAB
How to solve "Subscripted assignment... Learn more about subscripted assignment dimension mismatch
Copy. function s=my_function (A) hand=@ (x) Multiply_by_Ar (A,x); s=eigs (hand,1); The function Multiply_by_Ar returns, for a given A and x, the vector Ar*x, where the matrix Ar is related to A, but not equal to it. I then make a function handle which is basically multiplying by Ar and use the eigs function. It returns the problem.
Subscripted assignment dimension mismatch.. Learn more about matlab error
What you can do is to make Result1 a cell array. As an example, I'll just initialize Result1 as a cell array the same dimension as Result2 and just put a single randomly chosen integer from [-4 4] in each element.
1. There seems to be 3 problems with your code. First, the command [X, Y] = meshgrid(x_lim, y_lim) creates two 21x41 matrices and saves them to X and Y. So, the second line of your code ( [x(1), x(2)]= meshgrid(x_lim, y_lim);) is attempting to insert a 21x41 matrix into the first element of x, and a 21x41 matrix into the second element of x ...
the first time you run the code, Xsolution(:,idx) = X will create a Xsolution with the size of X. the second time you run it, the existing Xsolution does not fit the size of new X.. this is another reason why you always want to allocate the array before using it.
Subscripted assignment dimension mismatch error . Learn more about assigning arrays of different size Image Processing Toolbox
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错误提示：Subscripted assignment dimension mismatch.。. Learn more about matlab