eureka math grade 3 module 4 lesson 11 homework answers

• Texas Go Math
• Big Ideas Math
• Engageny Math
• McGraw Hill My Math
• enVision Math
• 180 Days of Math
• Math in Focus Answer Key
• Math Expressions Answer Key
• Privacy Policy

Eureka Math Grade 3 Module 4 Lesson 11 Answer Key

Engage ny eureka math 3rd grade module 4 lesson 11 answer key, eureka math grade 3 module 4 lesson 11 problem set answer key.

Answer: The area of the rectangle = 48 sq cm.

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 6 x 8 = 48. area of the rectangle = 48 sq cm.

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 8 x 6 = 48. area = 8 x 6 = (2 x 4) x 6. 2 x ( 4 x 6). 2 x 24. area of the rectangle = 48 sq cm.

Question 2. Does Problem 1 show all the possible whole number side lengths for a rectangle with an area of 48 square centimeters? How do you know?

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 8 x 6 = 48. area = 8 x 6 = (4 x 2) x 6. area = 4 x 12. area of the rectangle = 48 sq cm.

Question 3. In Problem 1, what happens to the shape of the rectangle as the difference between the side lengths gets smaller?

Answer: The area of the rectangle also decreases= 48 sq cm.

Answer: The area of the rectangle = 72 sq cm.

Explanation: In the above-given question, given that, area of the rectangle = l x b. where l = length, b = breadth. l = 8 cm and b = 9 cm given. area = l x b. area = 8 x 9. area = 72 sq cm.

b. Julius says a 4 cm by 18 cm rectangle has the same area as the rectangle in Part (a). Place parentheses in the equation to find the related fact and solve. Is Julius correct? Why or why not? 4 × 18 = 4 × 2 × 9 = 4 × 2 × 9 = ___8___ × __9____ = __72____ Area: __72___ sq cm

Answer: Yes, Julius was correct.

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 4 x 18 = 72. area = 4 x 18 = (4 x 2) x 9. area = 8 x 9. area of the rectangle = 72 sq cm.

c. Use the expression 8 × 9 to find different side lengths for a rectangle that has the same area as the rectangle in Part (a). Show your equations using parentheses. Then, estimate to draw the rectangle and label the side lengths.

Eureka Math Grade 3 Module 4 Lesson 11 Exit Ticket Answer Key

Answer: The area of the rectangle = 64 sq cm.

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 8 x 8 = 64. area = 8 x 8 = (4 x 2) x 8. area = 4 x 16. area of the rectangle = 64 sq cm.

Eureka Math Grade 3 Module 4 Lesson 11 Homework Answer Key

Answer: The area of the rectangle = 36 sq cm.

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 4 x 9 = 36. area = 4 x 9 = (4 x 3) x 3. area = 4 x 9. area of the rectangle = 36 sq cm.

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 1 x 36 = 36. area = 1 x 36 = (1 x 6) x 6. area = 6 x 6. area of the rectangle = 36 sq cm.

Question 2. Does Problem 1 show all the possible whole number side lengths for a rectangle with an area of 36 square centimeters? How do you know?

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 6 x 6 = 36. area = 6 x 6 = (6 x 2) x 3. area = 12 x 3. area of the rectangle = 36 sq cm.

b. Hilda says a 4 cm by 12 cm rectangle has the same area as the rectangle in Part (a). Place parentheses in the equation to find the related fact and solve. Is Hilda correct? Why or why not? 4 × 12 = 4 × 2 × 6 = 4 × 2 × 6 = __8____ × __6____ = ___48___ Area: __48____ sq cm

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 4 x 12 = 48. area = 4 x 12 = (4 x 2) x 6. area = 8 x 6. area of the rectangle = 48 sq cm.

c. Use the expression 8 × 6 to find different side lengths for a rectangle that has the same area as the rectangle in Part (a). Show your equations using parentheses. Then, estimate to draw the rectangle and label the side lengths.

Leave a Comment Cancel Reply

You must be logged in to post a comment.

Homework Helpers Samples

Homework Helpers provide step-by-step explanations of how (and why!) to work problems similar to those found in Eureka Math homework assignments. Check out a grade-level Homework Helper sample. Click here to purchase a full year of Homework Helpers in print. 

Homework Helpers Samples Grades K-12

Homework Helpers Sample Grade K

Homework Helpers Sample Grade 1

Homework Helpers Sample Grade 2

Homework Helpers Sample Grade 3

Homework Helpers Sample Grade 4

Homework Helpers Sample Grade 5

Homework Helpers Sample Grade 6

Homework Helpers Sample Grade 7

Homework Helpers Sample Grade 8

Homework Helpers Sample Algebra I (Grade 9)

Homework Helpers Sample Geometry (Grade 10)

Homework Helpers Sample Algebra II (Grade 11)

Homework Helpers Sample Pre-Calculus (Grade 12)

You are leaving greatminds.org.

Great Minds partners with a number of third party vendors to provide you with the best manipulatives and workbooks out there. You are about to visit one of our partner sites. Click below to open the site in a new window.