eureka math grade 5 module 6 lesson 20 homework

If you're seeing this message, it means we're having trouble loading external resources on our website.

If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked.

To log in and use all the features of Khan Academy, please enable JavaScript in your browser.

5th grade (Eureka Math/EngageNY)

Unit 1: module 1: place value and decimal fractions, unit 2: module 2: multi-digit whole number and decimal fraction operations, unit 3: module 3: addition and subtractions of fractions, unit 4: module 4: multiplication and division of fractions and decimal fractions, unit 5: module 5: addition and multiplication with volume and area, unit 6: module 6: problem solving with the coordinate plane.

Standards Alignment

Assessments, professional learning, family engagement, case studies.

NEW EUREKA MATH 2 ® PILOT PACKAGE

Are you looking for new ways to advance equity and build knowledge in your math classroom with high-quality instructional materials? EdReports recently reviewed Eureka Math 2 . Scan the QR code or access the final report .

Check out our special pilot package for only $10 per student.

Shop Online

SEE THE SCIENCE OF READING IN ACTION

At Great Minds ® , we’re committed to ensuring our curricula are aligned to the latest research on how students best learn to read, write, and build knowledge.

Explore webinars, blogs, research briefs, and more to discover how we incorporate this important body of research.

FREE CLASSROOM PRINTABLES

At Great Minds®, we’re committed to supporting educators with high-quality curricula and resources.

Explore resources designed to aid students in science and engineering and spark classroom conversation.

Webinar Library

Instructional resources, trending topics, knowledge-building, the science of reading, lesson design, universal design for learning (udl), background knowledge.

Palm Springs, CA

Houston, TX

New Orleans, LA

Eureka Math Student Materials: Grades K–5

Learn, Practice, Succeed

Learn, Practice, and Succeed from   Eureka Math™   offer teachers multiple ways to differentiate instruction, provide extra practice, and assess student learning. These versatile companions to   A Story of Units®   (Grades K–5) guide teachers in response to intervention (RTI), provide extra practice, and inform instruction.

Also available for Grades 6–8 . 

Learn, Practice, Succeed can be purchased all together or bundled in any configuration. Contact your account solutions manager for more information and pricing.  

The Learn book serves as a student’s in-class companion where they show their thinking, share what they know, and watch their knowledge build every day!

Application Problems:  Problem solving in a real-world context is a daily part of   Eureka Math , building student confidence and perseverance as students apply their knowledge in new and varied ways.

Problem Sets :  A carefully sequenced Problem Set provides an in-class opportunity for independent work, with multiple entry points for differentiation.

Exit Tickets:   These exercises check student understanding, providing the teacher with immediate, valuable evidence of the efficacy of that day’s instruction and informing next steps.

Templates:   Learn   includes templates for the pictures, reusable models, and data sets that students need for   Eureka Math   activities.

With   Practice , students build competence in newly acquired skills and reinforce previously learned skills in preparation for tomorrow’s lesson.   Together,   Learn   and   Practice   provide all the print materials a student uses for their core instruction.

Eureka Math  contains multiple daily opportunities to build fluency in   mathematics . Each is designed with the same notion—growing every student’s ability to use mathematics   with ease . Fluency experiences are generally fast-paced and energetic, celebrating improvement and focusing on recognizing patterns and connections within the material.

Eureka Math   fluency activities provide differentiated practice through a variety of formats—some are conducted orally, some use manipulatives, others use a personal whiteboard, or a handout and paper-and-pencil format.

Sprints:  Sprint fluency activities in  Eureka Math Practice  build speed and accuracy with already acquired skills. Used when students are nearing optimum proficiency, Sprints leverage tempo to build a low-stakes adrenaline boost that increases memory and recall. Their intentional design makes Sprints inherently differentiated – the problems build from simple to complex, with the first quadrant of problems being the simplest, and each subsequent quadrant adding complexity.

Eureka Math Succeed   enables students to work individually toward mastery.  Teachers and tutors can use  Succeed   books from prior grade levels as curriculum-consistent tools for filling gaps in foundational knowledge. Students will thrive and progress more quickly, as familiar models facilitate connections to their current, grade-level content.

Additional Problem Sets:  Ideal for Homework or extra practice, these additional problem sets align lesson-by-lesson with what is happening in the classroom. These problems are sequenced from simple-to-complex to naturally scaffold student practice. They align with   Eureka Math   and use the curriculum’s mathematical models and language, ensuring that students feel the connections and relevance to their daily instruction, whether they are working on foundational skills or getting extra practice on the current topic.

Homework Helpers:   Each problem set is accompanied by a Homework Helper, a set of worked examples that illustrate how similar problems are solved. The examples, viewed side by side with the homework, support students as they reinforce the day’s learning. Homework Helpers are also a great way to keep parents informed about math class.

Bundles and Class Sets Available

Bundle options are available for all of our materials (print, digital, PD, etc.). Prices vary by grade and size of class set. Certain grade-levels do not include all packets due to the nature of the grade-level content. Student workbooks are available in class sets of 20, 25, and 30. Prices vary by size of class set .

every child is capable of greatness

• Job Openings
• Digital Support
• Print Support
• Media Inquiries

Let’s Connect

• Terms of Service
• Privacy Policy
• System Status
• CA Residents: Do Not Sell My Info

• Yekaterinburg
• Novosibirsk
• Vladivostok

• Tours to Russia
• Practicalities
• Russia in Lists

Rusmania • Deep into Russia

Out of the Centre

Savvino-storozhevsky monastery and museum.

Zvenigorod's most famous sight is the Savvino-Storozhevsky Monastery, which was founded in 1398 by the monk Savva from the Troitse-Sergieva Lavra, at the invitation and with the support of Prince Yury Dmitrievich of Zvenigorod. Savva was later canonised as St Sabbas (Savva) of Storozhev. The monastery late flourished under the reign of Tsar Alexis, who chose the monastery as his family church and often went on pilgrimage there and made lots of donations to it. Most of the monastery’s buildings date from this time. The monastery is heavily fortified with thick walls and six towers, the most impressive of which is the Krasny Tower which also serves as the eastern entrance. The monastery was closed in 1918 and only reopened in 1995. In 1998 Patriarch Alexius II took part in a service to return the relics of St Sabbas to the monastery. Today the monastery has the status of a stauropegic monastery, which is second in status to a lavra. In addition to being a working monastery, it also holds the Zvenigorod Historical, Architectural and Art Museum.

Belfry and Neighbouring Churches

Located near the main entrance is the monastery's belfry which is perhaps the calling card of the monastery due to its uniqueness. It was built in the 1650s and the St Sergius of Radonezh’s Church was opened on the middle tier in the mid-17th century, although it was originally dedicated to the Trinity. The belfry's 35-tonne Great Bladgovestny Bell fell in 1941 and was only restored and returned in 2003. Attached to the belfry is a large refectory and the Transfiguration Church, both of which were built on the orders of Tsar Alexis in the 1650s.  

To the left of the belfry is another, smaller, refectory which is attached to the Trinity Gate-Church, which was also constructed in the 1650s on the orders of Tsar Alexis who made it his own family church. The church is elaborately decorated with colourful trims and underneath the archway is a beautiful 19th century fresco.

Nativity of Virgin Mary Cathedral

The Nativity of Virgin Mary Cathedral is the oldest building in the monastery and among the oldest buildings in the Moscow Region. It was built between 1404 and 1405 during the lifetime of St Sabbas and using the funds of Prince Yury of Zvenigorod. The white-stone cathedral is a standard four-pillar design with a single golden dome. After the death of St Sabbas he was interred in the cathedral and a new altar dedicated to him was added.

Under the reign of Tsar Alexis the cathedral was decorated with frescoes by Stepan Ryazanets, some of which remain today. Tsar Alexis also presented the cathedral with a five-tier iconostasis, the top row of icons have been preserved.

Tsaritsa's Chambers

The Nativity of Virgin Mary Cathedral is located between the Tsaritsa's Chambers of the left and the Palace of Tsar Alexis on the right. The Tsaritsa's Chambers were built in the mid-17th century for the wife of Tsar Alexey - Tsaritsa Maria Ilinichna Miloskavskaya. The design of the building is influenced by the ancient Russian architectural style. Is prettier than the Tsar's chambers opposite, being red in colour with elaborately decorated window frames and entrance.

At present the Tsaritsa's Chambers houses the Zvenigorod Historical, Architectural and Art Museum. Among its displays is an accurate recreation of the interior of a noble lady's chambers including furniture, decorations and a decorated tiled oven, and an exhibition on the history of Zvenigorod and the monastery.

Palace of Tsar Alexis

The Palace of Tsar Alexis was built in the 1650s and is now one of the best surviving examples of non-religious architecture of that era. It was built especially for Tsar Alexis who often visited the monastery on religious pilgrimages. Its most striking feature is its pretty row of nine chimney spouts which resemble towers.

Plan your next trip to Russia

Ready-to-book tours.

Your holiday in Russia starts here. Choose and book your tour to Russia.

REQUEST A CUSTOMISED TRIP

Looking for something unique? Create the trip of your dreams with the help of our experts.

• Texas Go Math
• Big Ideas Math
• Engageny Math
• McGraw Hill My Math
• enVision Math
• 180 Days of Math
• Math in Focus Answer Key
• Math Expressions Answer Key
• Privacy Policy

Eureka Math Grade 5 Module 4 Lesson 20 Answer Key

Engage ny eureka math 5th grade module 4 lesson 20 answer key, eureka math grade 5 module 4 lesson 20 problem set answer key.

Question 1. Convert. Show your work. Express your answer as a mixed number. (Draw a tape diagram if it helps you.) The first one is done for you.

a. 2 \(\frac{2}{3}\) yd = 8 ft 2 \(\frac{2}{3}\) yd = 2 \(\frac{2}{3}\) × 1 yd = 2 \(\frac{2}{3}\) × 3 ft = \(\frac{8}{3}\) × 3 ft = \(\frac{24}{3}\) ft = 8 ft

b. 1\(\frac{1}{2}\) qt = \(\frac{3}{8}\) gal 1\(\frac{1}{2}\) × 1 qt = 1 \(\frac{1}{2}\) × \(\frac{1}{4}\) gal = \(\frac{3}{2}\) × \(\frac{1}{4}\) gal = \(\frac{3}{8}\) gal.

c. 4 \(\frac{2}{3}\) ft = ______________ in 4 \(\frac{2}{3}\) × 1 ft = \(\frac{14}{3}\) × 12 in = \(\frac{168}{3}\) in = 56 in.

d. 9 \(\frac{1}{2}\) pt = ______________ qt 9 \(\frac{1}{2}\) × 1 pt =  \(\frac{19}{2}\) × \(\frac{1}{2}\) qt =  \(\frac{19}{4}\) qt = 4 \(\frac{3}{4}\) qt.

e. 3 \(\frac{3}{5}\) hr = ______________ min 3 \(\frac{3}{5}\) × 1 hr = \(\frac{18}{5}\) × 60 min = \(\frac{1080}{5}\) min = 216 mins.

f. 3 \(\frac{2}{3}\) ft = ______________ yd 3 \(\frac{2}{3}\) × 1 ft = \(\frac{11}{3}\) × \(\frac{1}{3}\) yd = \(\frac{11}{9}\) = 1 \(\frac{2}{9}\) yd.

Question 2. Three dump trucks are carrying topsoil to a construction site. Truck A carries 3,545 lb, Truck B carries 1,758 lb, and Truck C carries 3,697 lb. How many tons of topsoil are the 3 trucks carrying altogether?

Answer: The 3 trucks carrying altogether are 4.5 tons.

Explanation: Given that there are three dump trucks are carrying topsoil to a construction site and Truck A carries 3,545 lb, Truck B carries 1,758 lb, and Truck C carries 3,697 lb, so the total weight carried altogether is 3,545 + 1,758 + 3,697 = 9,000 lb. As each ton is 2000 pounds, so altogether the trucks are carrying is 9000 × \(\frac{1}{2000}\) which is 4.5 tons.

Question 3. Melissa buys 3\(\frac{3}{4}\) gallons of iced tea. Denita buys 7 quarts more than Melissa. How much tea do they buy altogether? Express your answer in quarts.

Answer: The total tea they bought is 37 quarts.

Explanation: Given that Melissa buys 3\(\frac{3}{4}\) gallons of iced tea, so total iced tea for Melissa is \(\frac{15}{4}\) which is 3.75. And Denita buys 7 quarts more than Melissa, so the total iced tea for Denita is, as 1 quart is 0.25 gallon and for 7 quarts it will be 7 × 0.25 which is 1.75 gallon. so the total iced tea for Denita is 1.75 + 3.75 which is 5.5. Then the total tea they bought is 3.75 + 5.5 = 9.25 gallon which is 9.25 × 4 = 37 quarts.

Question 4. Marvin buys a hose that is 27\(\frac{3}{4}\) feet long. He already owns a hose at home that is \(\frac{2}{3}\) the length of the new hose. How many total yards of hose does Marvin have now?

Answer: The total yards of hose does Marvin have now is 15 \(\frac{5}{12}\) yd.

Explanation: Given that Marvin buys a hose that is 27\(\frac{3}{4}\) feet long and he owns a hose at home that is \(\frac{2}{3}\) the length of the new hose, so \(\frac{2}{3}\) of 27\(\frac{3}{4}\) which is \(\frac{2}{3}\) × \(\frac{111}{4}\) = \(\frac{222}{12}\) = 18 \(\frac{1}{2}\), So the total yards of hose does Marvin have now is 27\(\frac{3}{4}\) + 18\(\frac{1}{2}\) = \(\frac{111}{4}\) + \(\frac{37}{2}\) = \(\frac{185}{4}\) = 46 \(\frac{1}{4}\). So total in yards, it will be 46 \(\frac{1}{4}\) × 1 yd = \(\frac{185}{4}\) × \(\frac{1}{3}\) yd = \(\frac{185}{12}\) =15 \(\frac{5}{12}\) yd.

Eureka Math Grade 5 Module 4 Lesson 20 Exit Ticket Answer Key

Convert. Express your answer as a mixed number.

a. 2\(\frac{1}{6}\) ft = ______________ in

Answer: 26 in.

Explanation: 2\(\frac{1}{6}\) ft = \(\frac{13}{6}\) × 1 ft = \(\frac{13}{6}\) × 12 in = \(\frac{156}{6}\) in = 26 in.

b. 3\(\frac{3}{4}\) ft = ______________ yd

Answer: 45 in.

Explanation: 3\(\frac{3}{4}\) ft = \(\frac{15}{4}\) ft × 1 ft = \(\frac{15}{4}\) × 12 in = \(\frac{180}{4}\) in = 45 in.

c. 2\(\frac{1}{2}\)c = ______________ pt

Answer: 1 \(\frac{1}{4}\) pt.

Explanation: 2\(\frac{1}{2}\)c = \(\frac{5}{2}\) × 1 c = \(\frac{5}{2}\) × \(\frac{1}{2}\) pt = \(\frac{5}{4}\) pt = 1 \(\frac{1}{4}\) pt.

d. 3\(\frac{2}{3}\) years = ______________ months

Answer: 44 months.

Explanation: 3\(\frac{2}{3}\) years = \(\frac{11}{3}\) × 1 year = \(\frac{11}{3}\) × 12 months = 44 months.

Eureka Math Grade 5 Module 4 Lesson 20 Homework Answer Key

Question 1. Convert. Show your work. Express your answer as a mixed number. The first one is done for you. 2 \(\frac{2}{3}\) yd = 8 ft 2 \(\frac{2}{3}\) yd = 2 \(\frac{2}{3}\) × 1 yd = 2 \(\frac{2}{3}\) × 3 ft = \(\frac{8}{3}\) × 3 ft = \(\frac{24}{3}\) ft = 8 ft

b. 1 \(\frac{1}{4}\) ft = \(\frac{5}{12}\) yd 1 \(\frac{1}{4}\) ft = 1 \(\frac{1}{4}\) × 1 ft = 1 \(\frac{1}{4}\) × \(\frac{1}{3}\) yd = \(\frac{5}{4}\) × \(\frac{1}{3}\) yd = \(\frac{5}{12}\) yd.

c. 3\(\frac{5}{6}\) ft = ______________ in

Answer: 46 in.

Explanation: 3\(\frac{5}{6}\) ft = 3\(\frac{5}{6}\) ft × 1 ft = \(\frac{23}{6}\) × 12 in = 46 in.

d. 7 \(\frac{1}{2}\) pt = ______________ qt

Answer: 3 \(\frac{3}{4}\) qt.

Explanation: 7 \(\frac{1}{2}\) pt = 7 \(\frac{1}{2}\) pt × 1 pt = \(\frac{15}{2}\) × \(\frac{1}{2}\) qt = \(\frac{15}{4}\) qt = 3 \(\frac{3}{4}\) qt.

e. 4\(\frac{3}{10}\) hr = ______________ min

Answer: 258 mins.

Explanation: 4\(\frac{3}{10}\) hr = 4\(\frac{3}{10}\) × 1 hr = \(\frac{43}{10}\) × 60 mins = 258 mins

f. 33 months = ______________ years

Answer: 2 \(\frac{3}{4}\) years.

Explanation: 33 × \(\frac{1}{12}\) = \(\frac{33}{12}\) = \(\frac{11}{4}\) = 2 \(\frac{3}{4}\) years.

Question 2. Four members of a track team run a relay race in 165 seconds. How many minutes did it take them to run the race?

Answer: The number of minutes did it take them to run the race is 2 \(\frac{3}{4}\) mins.

Explanation: Given that there are four members of a track team run a relay race in 165 seconds, so the number of minutes did it take them to run the race is 165 × \(\frac{1}{60}\) = \(\frac{11}{4}\) = 2 \(\frac{3}{4}\) mins.

Question 3. Horace buys 2\(\frac{3}{4}\) pounds of blueberries for a pie. He needs 48 ounces of blueberries for the pie. How many more pounds of blueberries does he need to buy?

Answer: Horace need more blueberries to buy is 0.25 pounds.

Explanation: Given that Horace buys 2\(\frac{3}{4}\) pounds of blueberries for a pie and he needs 48 ounces of blueberries for the pie, so the number of pounds of blueberries does he need to buy is, as 1 pound is 16 ounces and 1 ton is 2,200 pounds which is 32,000 ounces. As Horace needs 48 ounces of blueberries for the pie and we need to convert into ounce, so Horace need more blueberries to buy is 3 – 2\(\frac{3}{4}\) which is 3 – \(\frac{11}{4}\) = \(\frac{1}{4}\) = 0.25 pounds.

Question 4. Tiffany is sending a package that may not exceed 16 pounds. The package contains books that weigh a total of 9\(\frac{3}{8}\) pounds. The other items to be sent weigh \(\frac{3}{5}\) the weight of the books. Will Tiffany be able to send the package?

Answer: The total package is 15 pounds.

Explanation: Given that Tiffany is sending a package that may not exceed 16 pounds and the package contains books that weigh a total of 9\(\frac{3}{8}\) pounds and the other items to be sent weigh \(\frac{3}{5}\) the weight of the books. Let the book package be X and let the other package be Y. So from the above problem, X= 9\(\frac{3}{8}\) which is \(\frac{75}{8}\) and Y = \(\frac{3}{5}\) X = \(\frac{3}{5}\) × \(\frac{75}{8}\) = \(\frac{225}{40}\) = 5 \(\frac{5}{8}\). So the total package is X + Y = 9\(\frac{3}{8}\) + 5 \(\frac{5}{8}\) = \(\frac{75}{8}\) + \(\frac{225}{40}\) = \(\frac{600}{40}\) = 15 pounds.

Leave a Comment Cancel Reply

You must be logged in to post a comment.

Follow Puck Worlds online:

• Follow Puck Worlds on Twitter

Site search

Filed under:

• Kontinental Hockey League

Gagarin Cup Preview: Atlant vs. Salavat Yulaev

Share this story.

• Share this on Facebook
• Share this on Twitter
• Share this on Reddit
• Share All sharing options

Share All sharing options for: Gagarin Cup Preview: Atlant vs. Salavat Yulaev

Gagarin cup (khl) finals:  atlant moscow oblast vs. salavat yulaev ufa.

Much like the Elitserien Finals, we have a bit of an offense vs. defense match-up in this league Final.  While Ufa let their star top line of Alexander Radulov, Patrick Thoresen and Igor Grigorenko loose on the KHL's Western Conference, Mytischi played a more conservative style, relying on veterans such as former NHLers Jan Bulis, Oleg Petrov, and Jaroslav Obsut.  Just reaching the Finals is a testament to Atlant's disciplined style of play, as they had to knock off much more high profile teams from Yaroslavl and St. Petersburg to do so.  But while they did finish 8th in the league in points, they haven't seen the likes of Ufa, who finished 2nd. 

This series will be a challenge for the underdog, because unlike some of the other KHL teams, Ufa's top players are generally younger and in their prime.  Only Proshkin amongst regular blueliners is over 30, with the work being shared by Kirill Koltsov (28), Andrei Kuteikin (26), Miroslav Blatak (28), Maxim Kondratiev (28) and Dmitri Kalinin (30).  Oleg Tverdovsky hasn't played a lot in the playoffs to date.  Up front, while led by a fairly young top line (24-27), Ufa does have a lot of veterans in support roles:  Vyacheslav Kozlov , Viktor Kozlov , Vladimir Antipov, Sergei Zinovyev and Petr Schastlivy are all over 30.  In fact, the names of all their forwards are familiar to international and NHL fans:  Robert Nilsson , Alexander Svitov, Oleg Saprykin and Jakub Klepis round out the group, all former NHL players.

For Atlant, their veteran roster, with only one of their top six D under the age of 30 (and no top forwards under 30, either), this might be their one shot at a championship.  The team has never won either a Russian Superleague title or the Gagarin Cup, and for players like former NHLer Oleg Petrov, this is probably the last shot at the KHL's top prize.  The team got three extra days rest by winning their Conference Final in six games, and they probably needed to use it.  Atlant does have younger regulars on their roster, but they generally only play a few shifts per game, if that. 

The low event style of game for Atlant probably suits them well, but I don't know how they can manage to keep up against Ufa's speed, skill, and depth.  There is no advantage to be seen in goal, with Erik Ersberg and Konstantin Barulin posting almost identical numbers, and even in terms of recent playoff experience Ufa has them beat.  Luckily for Atlant, Ufa isn't that far away from the Moscow region, so travel shouldn't play a major role. 

I'm predicting that Ufa, winners of the last Superleague title back in 2008, will become the second team to win the Gagarin Cup, and will prevail in five games.  They have a seriously well built team that would honestly compete in the NHL.  They represent the potential of the league, while Atlant represents closer to the reality, as a team full of players who played themselves out of the NHL. 

• Atlant @ Ufa, Friday Apr 8 (3:00 PM CET/10:00 PM EST)
• Atlant @ Ufa, Sunday Apr 10 (1:00 PM CET/8:00 AM EST)
• Ufa @ Atlant, Tuesday Apr 12 (5:30 PM CET/12:30 PM EST)
• Ufa @ Atlant, Thursday Apr 14 (5:30 PM CET/12:30 PM EST)

Games 5-7 are as yet unscheduled, but every second day is the KHL standard, so expect Game 5 to be on Saturday, like an early start. 

Loading comments...